On Tue, Nov 8, 2011 at 5:24 AM, Jeroen Demeyer <jdeme...@cage.ugent.be> wrote:
> Currently, in sage-4.7.2:
>
> sage: integral_numerical(log(x), 0, 0)
> (nan, nan)
>
> Mathematically, the integral should certainly be zero: there is a
> primitive function which is continuous and defined at 0.  Symbolically,
> we can compute the integral correctly:
>
> sage: integral(log(x), (x,0,0))
> 0
>
> So I would like to add a special-case check for integral_numerical(): if
> the interval of integration is a point, then always return 0.
>
> I realize that this means that also the integral of 1/x from 0 to 0
> would be 0, even though 1/x has no continuous primitive at 0.  But
> according to the Lebesgue theory of integration, I think this is not
> even a problem.

Quick remark:  I hope you don't do this for everything, e.g., for
dirac_delta, since

sage: integral_numerical(dirac_delta, 0,0)
0

would suck.  In this case, dirac_delta is actually a distribution.  It
is defined as the distribution with the property that

 integral(dirac_delta, a, b)

is 0 if the interval [a,b] does not contain 0, and is 1 if the
interval [a,b] does contain 0.

Right now we get a TypeError when trying to evaluate the above, which
is unfortunate too, but at least it's an error rather than a totally
wrong answer.   With your patch, probably Sage would silently produce
a wrong answer.

 -- William

>
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-- 
William Stein
Professor of Mathematics
University of Washington
http://wstein.org

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