> > Is the following the intended behaviour? > > > sage: type(15.mod(4)) > > <type 'sage.rings.integer.Integer'> > > sage: type(mod(15, 4).lift()) > > <type 'sage.rings.integer.Integer'> > > sage: 15.mod(4) == 7 > > False > > sage: mod(15, 4).lift() == 7 > > False
Sorry, I should have said what was the intended behavior. We were expecting mod to behave the same whether it is called as a method of a integer or as a global function. For instance, the following functions behave the same : sage: 15.factor() 3 * 5 sage: factor(15) 3 * 5 sage: real(1+i) 1 sage: (1+i).real() 1 sage: type(real(1+i)) <type 'sage.symbolic.expression.Expression'> sage: type((1+i).real()) <type 'sage.symbolic.expression.Expression'> which is not the case for mod : sage: type(mod(15,4)) <type 'sage.rings.integer_mod.IntegerMod_int'> sage: type(15.mod(4)) <type 'sage.rings.integer.Integer'> We are happy with using % if we really want the remainder as a normal integer. Sébastien -- To post to this group, send an email to sage-devel@googlegroups.com To unsubscribe from this group, send an email to sage-devel+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URL: http://www.sagemath.org
