On 21 February 2010 22:22, David Roe <r...@math.harvard.edu> wrote: > I think that the reason for having mod behave the way it does is that the > percent operator is defined by __mod__. > > Personally, I have no strong preference as to whether a.mod(b) behaves like > a % b (ie a.__mod__(b)) or like mod(a, b). > David
Perhaps we should have a different way of constructing elements of Z/nZ? Of course there is Integers(n)(m). What about Mod(m,n) with a capital M? John -- To post to this group, send an email to sage-devel@googlegroups.com To unsubscribe from this group, send an email to sage-devel+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URL: http://www.sagemath.org
