On Fri, May 23, 2008 at 9:40 AM, Jason Grout
<[EMAIL PROTECTED]> wrote:
>
> Jason Grout wrote:
>> In the recent discussion "Change the default base_ring for matrices from
>> ZZ to QQ", there were lots of opinions shared, and William summarized
>> some feelings from the group, but it wasn't a solid conclusion (at
>> least, based on an IRC conversation, William is rethinking the conclusion).
>>
>> Here are two (somewhat competing) proposals, one from an IRC discussion
>> with William just now and the other from William's summary from the
>> previous thread.
>>
>> Proposal A:
>>
>> If a ring is not specified in a matrix() call, and the elements provided
>> are all integers (or if there are no elements provided), then the base
>> ring would default to QQ (instead of ZZ, as would currently happen).
>>
>> Reasons (from William and from discussions with a linear algebra person):
>>
>> 1. "linear algebra" is over fields (as opposed to module theory).  When
>> commonly-created matrices (i.e., ones with integer entries or with no
>> specified entries) "default" to non-fields, the behavior is very
>> surprising to linear algebra people and casual users (like linear
>> algebra students, for example).
>>
>> 2. the matrix() command was designed for ease of use for "casual end users"
>>
>> 3. It is very easy to explicitly specify a ring, either in matrix() or
>> via MatrixSpace
>>
>>
>> So here are the cases we would see a change in behavior
>>
>> matrix(3,3) would return a 3x3 zero matrix over QQ instead of over ZZ
>>
>> matrix(3,range(9)) would return a 3x3 matrix over QQ instead of over ZZ.
>>
>>
>> Proposal B (from William's summary on the previous thread):
>>
>> Leave matrix() as-is.  Rename echelon_form to hermite_form, and make a
>> new echelon_form function that computes hermite_form over the fraction
>> field of the base ring.
>
>
> It sounds like the popular vote selects proposal B.  This is being
> tracked at #3211.
>

As BDFL (and person who supported A instead of B overall), and now
agree that by popular vote we should do B.

 -- William

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