Given a matrix, I want to obtain a 0/1-matrix with 1 if and only if the
corresponding entry was 0.
What is the fastest way of doing this?
This is how I currently do it:
R = ZZ
zero = R(0)
one = R(1)
def is_zero(x):
if x:
return zero
else:
return one
incidence_matrix = slack_matrix.apply_map(is_zero, R=R)
Strangely, this takes up a lot of time. With
https://trac.sagemath.org/ticket/29837 this appears to be the bottle neck
of computing the incidence matrix for polyhedra, which would be strange.
Can somebody help? Thank you.
Jonathan
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