Dear SM or MS

With this geometry the incident beam to sample angle (alpha) is usually fixed 
at a small value (say, 2 - 10degrees).

If you have the ability to scan the sample axis (omega - i.e. changing alpha), 
then (i) conduct an omega scan (this could be done manually if necessary), (ii) 
extract individual intensities of peaks of interest, (iii) correct the peak 
intensities for the geometry used*, and (iv) plot the corrected intensities as 
a function of alpha. If you have preferred orientation along a specific 
direction them the plot should show a maximum at  (alpha = 0.5 * 2Theta) for 
that reflection. If there is no preferred orientation, then the plot of 
corrected intensities should have a constant value as a function of alpha.


* This intensity correction is fairly simple and takes into account the 
difference in beam path for the incident and diffracted beams. It relies on 
knowledge of the incident beam to sample angle (alpha) and the diffracted beam 
to sample angle (beta) where (alpha + beta) = 2Theta. It has been described 
nicely by Toraya et al

H. Toraya, T. C. Huang and Y. Wu

Intensity enhancement in asymmetric diffraction with parallel-beam synchrotron 
radiation

J. Appl. Cryst. (1993). 26, 774-777    [ doi:10.1107/S0021889893004881 ]

Cheers

o----------------------------oo0oo----------------------------o
     Ian Madsen
     Team Leader - Diffraction Science
     CSIRO Process Science and Engineering
     Box 312,  Clayton South 3169
     Victoria,   AUSTRALIA
     Phone +61 3 9545 8785 direct
                 +61 3 9545 8500 switch
                 +61 (0) 417 554 935 mobile
     FAX    +61 3 9562 8919
     Email ian.mad...@csiro.au
o----------------------------oo0oo----------------------------o

From: rietveld_l-requ...@ill.fr [mailto:rietveld_l-requ...@ill.fr] On Behalf Of 
SM
Sent: Tuesday, 25 March 2014 3:19 PM
To: rietveld_l@ill.fr
Subject: PO in parallel beam flat-plat geometry -reg

Dear all,
please clarify my doubt, this may be very old one, even though please clarify

how to find Preferred Orientation in parallel beam flat-plat geometry with CPS 
detector.

kindly clarify my doubt

Thank you,

regards
MS
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