Even if all statements are true, this sounds like a classic case of choosing 
how to present your results so they appear in the best possible light for 
publication. 


Andrew Mauer-Oats
Mathematics Ph.D.
Chicago Public Schools: Whitney Young


> On Apr 13, 2015, at 4:16 PM, Josh Grams <[email protected]> wrote:
> 
> That is helpful, but my basic objection still stands: you're computing
> with *times* while the claim in the article was about *speeds*, I think.
> He says "50% more work using the same amount of CPU cycles", which I
> read as work/time.  So you need to take the reciprocal of all your
> values.  Don't you?
> 
>> On 2015-04-13 08:15AM, George Neuner wrote:
>> So:
>> percent change = 100% * ( (new - old) / old )
>> Dropping the common multiplier to keep the numbers simple:
>> 
>> 3.7 -> 3.8
>> percent change = 100% * ( (95 - 143) / 143 )
>>               = 100% * ( -48 / 143 )
>>               = 100% * ( -0.34 )
>>               = -34%
> 
> Should be:
> 
> 3.7 -> 3.8
> percent change = 100% * ( ( (1/95) - (1/143) ) / (1/143) )
>               = 100% * ( ( 0.0105 - 0.00699 ) / (0.00699) )
>               = 100% * ( 0.0351 / .00699 )
>               = 100% * ( .50 )
>               = 50%
> 
> Yes? No? Maybe I'm reading the article wrong...
> 
> --Josh
> 

-- 
You received this message because you are subscribed to the Google Groups 
"Racket Users" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to [email protected].
For more options, visit https://groups.google.com/d/optout.

Reply via email to