(=~ is interesting. Thanks.
On 22 October 2013 13:53, Matthias Felleisen <matth...@ccs.neu.edu> wrote: > > ;; equation3 : number -> boolean > ;; to determine whether n is a solution for 2n^2 = 102 > (define (equation3 n) > (=~ (* 2 n n) 102 .001)) > > > -- Matthias > > > > On Oct 22, 2013, at 8:40 AM, Bo Gus <foruman...@gmail.com> wrote: > > > equation 2 is 2n^2 = 102 so I implement like this: > > > > ;; equation3 : number -> boolean > > ;; to determine whether n is a solution for 2n^2 = 102 > > (define (equation3 n) > > (= (* 2 n n) 102)) > > > > And my answer is the same as per the online answer. so great. > > > > But how can I check a valid answer. > > > > Eg if I do: > > > > (equation3 (sqrt 51)) > > >false > > > > same using - square root 51. > > > > How can I fix this? Is the only way to do a range check? Eg have some > sort of tolerance - eg between 0.01 above and below answer? Any other > ideas? > > > > ____________________ > > Racket Users list: > > http://lists.racket-lang.org/users > >
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