equation 2 is 2n^2 = 102 so I implement like this: ;; equation3 : number -> boolean ;; to determine whether n is a solution for 2n^2 = 102 (define (equation3 n) (= (* 2 n n) 102))
And my answer is the same as per the online answer. so great. But how can I check a valid answer. Eg if I do: (equation3 (sqrt 51)) >false same using - square root 51. How can I fix this? Is the only way to do a range check? Eg have some sort of tolerance - eg between 0.01 above and below answer? Any other ideas?
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