On Mon, Sep 17, 2012 at 10:40 AM, Ashley Fowler
<afowl...@broncos.uncfsu.edu> wrote:
> Basically delete-second2 has to take a input of a list, if the list has more 
> than 1 item then it will delete the second item and return the new list, if 
> it doesnt have more than 1 item it will just return the original list.


Let me be a bit more explicit.


Is delete-second1 any different from delete-second2?

   * If it is the exact same problem, you get to just copy your answer
from delete-second1 over to delete-second2.  :)

   *  If it is slightly different, then you can _reuse_ some of the
hard work you did to solve delete-second1.

   * If there's no similarity whatsoever, then you have to design the
function from scratch.


Which one of these cases matches?
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