Are you saying the problem is not on-line? There must be some context. -- Matthias
On Sep 17, 2012, at 12:22 PM, Ashley Fowler wrote: > That was the full problem. It started with #2. I'm just confused on how to > start #3. I know you have to use a if expression. > > 2. Write a procedure (delete-second1 LS) that takes a list LS of at > least two items and returns the same list only with the second item > deleted. You may assume the input list has at least two elements. > > Tests: > (delete-second1 '(3 7)) ==> (3) > (delete-second1 '(a b c d)) ==> (a c d) > > 3. Write a procedure (delete-second2 LS) that takes an arbitrary list > LS of items and returns the same list only with the second item deleted > if there is a second item, o.w. returns original input list. > Hint: you will need to use a conditional. > > Tests: > (delete-second2 '()) ==> () > (delete-second2 '(3)) ==> (3) > (delete-second2 '(3 7)) ==> (3) > (delete-second2 '(a b c d)) ==> (a c d) > ________________________________________ > From: Matthias Felleisen [matth...@ccs.neu.edu] > Sent: Monday, September 17, 2012 12:16 PM > To: Ashley Fowler > Cc: users@racket-lang.org > Subject: Re: [racket] Delete Second > > On Sep 17, 2012, at 12:11 PM, Ashley Fowler wrote: > >> I just wanna know if I am starting the procedure out right? This is what I >> got so far... >> (define delete-second2(lambda(ls) >> (if(>ls 1) > > > Since you're asking a yes-no question, the answer has to be 'no'. > > Can you point us to the full problem statement please? The 'tests' > specification looks wrong -- Matthias > >
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