Folks: Rolf's (appropriate, in my view) response below seems symptomatic of an increasing tendency of posters to hide their identities with pseudonyms and fake headers. While some of this may be due to identity paranoia (which I think is overblown for this list), I suspect that a good chunk of it is lazy students trying to beat the system by having us do their homework. The etiquette of this list has traditionally been, like the software, open: we sign our names. I would urge helpeRs to adhere to this etiquette and ignore unsigned posts.
Contrary views welcome, either via public or private responses. -- Bert Bert Gunter Genentech Nonclinical Statistics -----Original Message----- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Rolf Turner Sent: Wednesday, March 03, 2010 6:42 PM To: Pitmaster Cc: r-help@r-project.org Subject: Re: [R] Setting graphical parameters Do your own <expletive deleted> homework! It looks pretty trivial; what's your problem? cheers, Rolf Turner On 4/03/2010, at 2:39 PM, Pitmaster wrote: > > Hi guys... I have problem with this excersise... > > Consider the pressure data frame again. > > (a) Plot pressure against temperature, and use the following > command to pass a curve through these data: > >> curve((0.168 + 0.007*x)(20/3), from=0, to=400, add=TRUE) > > (b) Now, apply the power transformation y3/20 to the pressure data values. > Plot these transformed values against temperature. Is a linear > or nonlinear relationship evident now? Use the abline() function > to pass a straight line through the points. (You need an intercept > and slope for this see the previous part of this question to obtain > appropriate values.) > > (c) Add a suitable title to the graph. > > (d) Re-do the above plots, but use the mfrow() function to display > them in a 2 × 1 layout on the graphics page. Repeat once again > using a 1 × 2 layout. > > DATA: >> pressure > temperature pressure > 1 0 0.0002 > 2 20 0.0012 > 3 40 0.0060 > 4 60 0.0300 > 5 80 0.0900 > 6 100 0.2700 > 7 120 0.7500 > 8 140 1.8500 > 9 160 4.2000 > 10 180 8.8000 > 11 200 17.3000 > 12 220 32.1000 > 13 240 57.0000 > 14 260 96.0000 > 15 280 157.0000 > 16 300 247.0000 > 17 320 376.0000 > 18 340 558.0000 > 19 360 806.0000 > > > Can anyone know the solution ? ###################################################################### Attention: This e-mail message is privileged and confidential. If you are not the intended recipient please delete the message and notify the sender. Any views or opinions presented are solely those of the author. This e-mail has been scanned and cleared by MailMarshal www.marshalsoftware.com ###################################################################### ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.