Hi guys... I have problem with this excersise... Consider the pressure data frame again.
(a) Plot pressure against temperature, and use the following command to pass a curve through these data: > curve((0.168 + 0.007*x)ˆ(20/3), from=0, to=400, add=TRUE) (b) Now, apply the power transformation y3/20 to the pressure data values. Plot these transformed values against temperature. Is a linear or nonlinear relationship evident now? Use the abline() function to pass a straight line through the points. (You need an intercept and slope for this – see the previous part of this question to obtain appropriate values.) (c) Add a suitable title to the graph. (d) Re-do the above plots, but use the mfrow() function to display them in a 2 × 1 layout on the graphics page. Repeat once again using a 1 × 2 layout. DATA: > pressure temperature pressure 1 0 0.0002 2 20 0.0012 3 40 0.0060 4 60 0.0300 5 80 0.0900 6 100 0.2700 7 120 0.7500 8 140 1.8500 9 160 4.2000 10 180 8.8000 11 200 17.3000 12 220 32.1000 13 240 57.0000 14 260 96.0000 15 280 157.0000 16 300 247.0000 17 320 376.0000 18 340 558.0000 19 360 806.0000 Can anyone know the solution ? -- View this message in context: http://n4.nabble.com/Setting-graphical-parameters-tp1577529p1577529.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
