I think that is.na(x) <- i generally does the same to x as does x[i] <- NA
I say 'generally' because some classes (e.g., numeric_version) do not allow x[i]<-NA but do allow is.na(x)<-i. It is possible that some classes mess up this equivalence, but I think that would be considered a bug. -Bill On Fri, Dec 16, 2022 at 10:29 AM Göran Broström <goran.brost...@umu.se> wrote: > I'm confused: > > > x <- 1:2 > > is.na(x) <- 1 > > x > [1] NA 2 > > OK, but > > > x <- c("A", "B") > > is.na(x) <- "A" > > x > A > "A" "B" NA > > What happens? > > G_ran > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.