On Wed, Jul 23, 2008 at 4:03 PM, Shubha Vishwanath Karanth <[EMAIL PROTECTED]> wrote: > Hi R, > > > > Let, > > > > x=1:80 > > > > I want to sum up first 8 elements of x, then again next 8 elements of x, > then again another 8 elements..... So, my new vector should look like: > > c(36,100,164,228,292,356,420,484,548,612) > > > > I used: > > > > aggregate(x,list(rep(1:10,each=8)),sum)[-1] > > or > > rowsum(x,group=rep(1:10,each=8)) > > > > > > But without grouping, can I achieve the required? Any other ways of > doing this? > > > > Thanks, Shubha > >
How about x<-1:80 filter(x,rep(1,8),"convolution",sides=1)[seq(8,length(x),by=8)] ##or cumsum(x)[seq(8,length(x),by=8)] ? /Gustaf -- Gustaf Rydevik, M.Sci. tel: +46(0)703 051 451 address:Essingetorget 40,112 66 Stockholm, SE skype:gustaf_rydevik ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
