Dear Shubha,
Try this:
x=1:80
tapply(x,rep(1:10,each=8),sum)
1 2 3 4 5 6 7 8 9 10
36 100 164 228 292 356 420 484 548 612
HTH,
Jorge
On Wed, Jul 23, 2008 at 10:03 AM, Shubha Vishwanath Karanth <
[EMAIL PROTECTED]> wrote:
> Hi R,
>
>
>
> Let,
>
>
>
> x=1:80
>
>
>
> I want to sum up first 8 elements of x, then again next 8 elements of x,
> then again another 8 elements..... So, my new vector should look like:
>
> c(36,100,164,228,292,356,420,484,548,612)
>
>
>
> I used:
>
>
>
> aggregate(x,list(rep(1:10,each=8)),sum)[-1]
>
> or
>
> rowsum(x,group=rep(1:10,each=8))
>
>
>
>
>
> But without grouping, can I achieve the required? Any other ways of
> doing this?
>
>
>
> Thanks, Shubha
>
>
>
> This e-mail may contain confidential and/or privileged i...{{dropped:13}}
>
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