Hello,
Inline.
Às 22:44 de 29/04/20, Ana Marija escreveu:
Hi Rui,
thanks for getting back to me
so I tried your method and I got:
sum(b$PHENO==2, na.rm=T)
[1] 828
sum(b$PHENO==1, na.rm=T)
[1] 859
Can you please tell me if
b$PHENO <- (b$FLASER == 2 | b$PLASER == 2) + 1L
just assigns PHENO=2 if b$FLASER == 2 | b$PLASER == 2 and everything else is 1?
Yes, that's it. If b$FLASER == 2 | b$PLASER == 2 returns TRUE then
adding 1 will give
TRUE + 1 -> 1 + 1 -> 2
This is because logical values are internally coded as integers 0 and 1.
And if the condition returns FALSE it becomes
FALSE + 1 -> 0 + 1 -> 1
In both cases the result is what you want.
Please see how my data looks like:
sum(b$FLASER==2, na.rm=T)
[1] 92
sum(b$FLASER==1, na.rm=T)
[1] 1533
sum(b$PLASER==1, na.rm=T)
[1] 850
sum(b$PLASER==2, na.rm=T)
[1] 806
dim(b)
[1] 1698 5
unique(b$FLASER)
[1] 1 3 2 NA
unique(b$PLASER)
[1] 1 2 3 NA
What I write above is valid even if your data contains NA's, like it
does. This is because
(TRUE | x) == (x | TRUE) == TRUE
even if x is NA.
This is an example with some NA values in the data.
set.seed(1234)
b <- rbind(b, b)
i <- sample(nrow(b), 3)
b$FLASER[i] <- NA
i <- sample(nrow(b), 2)
b$PLASER[i] <- NA
b$PLASER[10] <- 2
b$PHENO <- (b$FLASER == 2 | b$PLASER == 2) + 1
b
As you can see,
row 5:
b$FLASER is NA, b$PLASER == 2 evaluates to TRUE -> b$PHENO is TRUE
row 10:
b$FLASER == 2 evaluates to TRUE, b$PLASER is NA -> b$PHENO is TRUE
So the code is not broken by NA's
Hope this helps,
Rui Barradas
On Wed, Apr 29, 2020 at 4:10 PM Rui Barradas <ruipbarra...@sapo.pt> wrote:
Hello,
Here is another way. The condition returns FALSE/TRUE or 0/1. Add 1 to
get the expected result.
It has the advantage of being faster.
b$PHENO <- (b$FLASER == 2 | b$PLASER == 2) + 1L
Hope this helps,
Rui Barradas
Às 20:42 de 29/04/20, Ana Marija escreveu:
Thanks, I did this:
b$PHENO<- ifelse(b$FLASER ==2 | b$PLASER ==2, 2, 1)
On Wed, Apr 29, 2020 at 2:36 PM Ivan Krylov <krylov.r...@gmail.com> wrote:
On Wed, 29 Apr 2020 14:19:18 -0500
Ana Marija <sokovic.anamar...@gmail.com> wrote:
My conditions for creating a new column PHENO would be this:
if FLASER or PLASER =2 then PHENO=2
otherwise PHENO=1
On Wed, 29 Apr 2020 15:30:45 -0400
"Patrick (Malone Quantitative)" <mal...@malonequantitative.com> wrote:
If you don't mind using tidyverse, you can do this easily with
if_else.
...and if you want to stay with base R, you can use the ifelse
function.
--
Best regards,
Ivan
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
