Hello,
Here is another way. The condition returns FALSE/TRUE or 0/1. Add 1 to
get the expected result.
It has the advantage of being faster.
b$PHENO <- (b$FLASER == 2 | b$PLASER == 2) + 1L
Hope this helps,
Rui Barradas
Às 20:42 de 29/04/20, Ana Marija escreveu:
Thanks, I did this:
b$PHENO<- ifelse(b$FLASER ==2 | b$PLASER ==2, 2, 1)
On Wed, Apr 29, 2020 at 2:36 PM Ivan Krylov <krylov.r...@gmail.com> wrote:
On Wed, 29 Apr 2020 14:19:18 -0500
Ana Marija <sokovic.anamar...@gmail.com> wrote:
My conditions for creating a new column PHENO would be this:
if FLASER or PLASER =2 then PHENO=2
otherwise PHENO=1
On Wed, 29 Apr 2020 15:30:45 -0400
"Patrick (Malone Quantitative)" <mal...@malonequantitative.com> wrote:
If you don't mind using tidyverse, you can do this easily with
if_else.
...and if you want to stay with base R, you can use the ifelse
function.
--
Best regards,
Ivan
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