Why? I suspect that there is no reason that you need to do this.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Thu, Jun 13, 2019 at 1:22 PM Tina Chatterjee <tinamunim2...@gmail.com>
wrote:
> Hello everyone!
> I have the following dataframe(df).
>
> a<-c("a1","a2","a2","a1","a1","a1")
> b<-c("b1","b1","b1","b1","b1","b2")
> c<-c("c1","c1","c1","c1","c1","c2")
> time <- c(runif(6,0,1))
>
> df<-data.frame(a,b,c,time)
> df
>
> a b c time
> 1 a1 b1 c1 0.28781082
> 2 a2 b1 c1 0.02102591
> 3 a2 b1 c1 0.72479220
> 4 a1 b1 c1 0.41947675
> 5 a1 b1 c1 0.58899855
> 6 a1 b2 c2 0.82414123
>
> Now, I want to extract the time components corresponding
> to the specific combination of the factors. Finally I have made a dataframe
> (df_1) with 2 columns one with the time components and the other with the
> level combinations.
>
> df[df$a=="a1" & df$b=="b1" & df$c=="c1",]$time
> df[df$a=="a2" & df$b=="b1" & df$c=="c1",]$time
> df[df$a=="a1" & df$b=="b2" & df$c=="c2",]$time
>
> val <- c(df[df$a=="a1" & df$b=="b1" & df$c=="c1",]$time,df[df$a=="a2" &
> df$b=="b1" & df$c=="c1",]$time,df[df$a=="a1" & df$b=="b2" &
> df$c=="c2",]$time)
> name <- c(rep("a1b1c1",3),rep("a2b1c1",2),"a1b2c2")
> df_1 <- data.frame(val,name)
>
> I made it manually. In reality I have a lot of treatment combinations. So,
> could you please suggest how can I do this with a loop or any control
> sequence?
> Thanks and regards.
> Tina
>
> [[alternative HTML version deleted]]
>
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>
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