How about just
df$time[match(paste(df$a, df$b, df$c), c(
"co mb o1",
..
"co mb oN"))]
On Fri, 14 Jun 2019 at 08:22, Tina Chatterjee <tinamunim2...@gmail.com>
wrote:
> Hello everyone!
> I have the following dataframe(df).
>
> a<-c("a1","a2","a2","a1","a1","a1")
> b<-c("b1","b1","b1","b1","b1","b2")
> c<-c("c1","c1","c1","c1","c1","c2")
> time <- c(runif(6,0,1))
>
> df<-data.frame(a,b,c,time)
> df
>
> a b c time
> 1 a1 b1 c1 0.28781082
> 2 a2 b1 c1 0.02102591
> 3 a2 b1 c1 0.72479220
> 4 a1 b1 c1 0.41947675
> 5 a1 b1 c1 0.58899855
> 6 a1 b2 c2 0.82414123
>
> Now, I want to extract the time components corresponding
> to the specific combination of the factors. Finally I have made a dataframe
> (df_1) with 2 columns one with the time components and the other with the
> level combinations.
>
> df[df$a=="a1" & df$b=="b1" & df$c=="c1",]$time
> df[df$a=="a2" & df$b=="b1" & df$c=="c1",]$time
> df[df$a=="a1" & df$b=="b2" & df$c=="c2",]$time
>
> val <- c(df[df$a=="a1" & df$b=="b1" & df$c=="c1",]$time,df[df$a=="a2" &
> df$b=="b1" & df$c=="c1",]$time,df[df$a=="a1" & df$b=="b2" &
> df$c=="c2",]$time)
> name <- c(rep("a1b1c1",3),rep("a2b1c1",2),"a1b2c2")
> df_1 <- data.frame(val,name)
>
> I made it manually. In reality I have a lot of treatment combinations. So,
> could you please suggest how can I do this with a loop or any control
> sequence?
> Thanks and regards.
> Tina
>
> [[alternative HTML version deleted]]
>
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