Like this:
for (i in files_rwl) {
thisfile <- get(i)
thisfile[is.na(thisfile)] <- 0
assign(i, thisfile)
}
It's likely that you could condense it, but using the long form makes it
clear what's happening.
Sarah
--
Sarah Goslee
http://www.functionaldiversity.org
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
