Hi,
cimfasy_rwl[ is.na(cimfasy_rwl) ] <-0
Or did I understood Your right?
HTH,
Kimmo
Alfredo Alessandrini wrote:
I'm trying to replace NA with 0 value...
I've write a loop, but don't work...
Where's the problem?
cimfasy_rwl
1991 0.92 0.72 0.50 1.29 0.54 1.22
1992 2.15 1.28 1.23 2.26 1.22 3.17
1993 1.50 0.87 1.68 1.97 0.83 2.55
1994 0.69 0.00 0.76 1.89 0.60 0.87
1995 1.13 1.04 1.19 1.52 1.13 1.78
1996 1.15 0.92 1.50 0.97 0.60 NA
1997 NA NA NA NA NA NA
1998 NA NA NA NA NA NA
1999 NA NA NA NA NA NA
2000 NA NA NA NA NA NA
files_rwl <- ls(pattern="_rwl$")
files_rwl
[1] "cimfasy_rwl" "rocquce_rwl"
for (i in files_rwl) assign(i,i[is.na(i)] <- 0)
ls()
[1] "cimfasy_rwl" "files_rwl" "files.rwl" "i" "rocquce_rwl"
cimfasy_rwl
[1] 0
Thanks in advance,
Alfredo
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and provide commented, minimal, self-contained, reproducible code.