[See in-line below]
On 17-Nov-2013 22:38:30 Rolf Turner wrote:
>
> (1) The backslashes are not really there; they are an artefact of the R
> print() function.
> Try cat(u,"\n"). I think this might be an FAQ.
>
> (2) Is not your problem the fact that your are setting "replacement"
> equal to the
> thing you are trying to get rid of? I.e. don't you want
>
> v <- gsub(pattern='\"',replacement='',x=u) ???
>
> Either I am misunderstanding your intent or you need another cup of coffee.
Is the above line a Fortune?
> cheers,
>
> Rolf
>
> On 11/18/13 11:07, Erin Hodgess wrote:
>> Dear R People:
>>
>> I'm sure that this is a very simple problem, but I have been wresting with
>> it for some time.
>>
>> I have the following file that has the following one line:
>>
>> CRS("+init=epsg:28992")
>>
>> Fair enough. I scan it into R and get the following:
>>
>>> u
>> [1] "CRS(\"+init=epsg:28992\")"
>>> gsub(pattern='\"',replacement='"',x=u)
>> [1] "CRS(\"+init=epsg:28992\")"
>>
>> I need to get rid of the extra quotation marks and slashes. I've tried all
>> sorts of things, including gsub, as you see, but no good.
>
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-------------------------------------------------
E-Mail: (Ted Harding) <ted.hard...@wlandres.net>
Date: 17-Nov-2013 Time: 23:55:48
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