I actually solved the problem in a backhanded (backslashed?) sort of
way...took out the quotation marks in the original file. All is well.
Thanks!
On Sun, Nov 17, 2013 at 4:38 PM, Rolf Turner <r.tur...@auckland.ac.nz>wrote:
>
> (1) The backslashes are not really there; they are an artefact of the R
> print() function.
> Try cat(u,"\n"). I think this might be an FAQ.
>
> (2) Is not your problem the fact that your are setting "replacement" equal
> to the
> thing you are trying to get rid of? I.e. don't you want
>
> v <- gsub(pattern='\"',replacement='',x=u) ???
>
> Either I am misunderstanding your intent or you need another cup of coffee.
>
> cheers,
>
> Rolf
>
>
> On 11/18/13 11:07, Erin Hodgess wrote:
>
>> Dear R People:
>>
>> I'm sure that this is a very simple problem, but I have been wresting with
>> it for some time.
>>
>> I have the following file that has the following one line:
>>
>> CRS("+init=epsg:28992")
>>
>> Fair enough. I scan it into R and get the following:
>>
>> u
>>>
>> [1] "CRS(\"+init=epsg:28992\")"
>>
>>> gsub(pattern='\"',replacement='"',x=u)
>>>
>> [1] "CRS(\"+init=epsg:28992\")"
>>
>> I need to get rid of the extra quotation marks and slashes. I've tried
>> all
>> sorts of things, including gsub, as you see, but no good.
>>
>
--
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodg...@gmail.com
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