On 2013-10-14 10:04, David Epstein wrote:
lm(height ~ ., data=X)
works fine.
However
nnn <- "height" ; lm(nnn ~ . ,data=X)
fails
How do I write such a formula, which depends on the value of a string
variable like nnn above?
as.formula() with paste() could work, but from where you are now, try
lm(get(nnn) ~ . ,data=X)
HTH
A typical application might be a program that takes a data frame
containing only numerical data, and figures out which of the columns
can be best predicted from all the other columns.
Thanks
David
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