This being R, there are likely other ways, but I use: lm(as.formula(paste(nnn, "~ .")),data=X)
Sarah On Sun, Oct 13, 2013 at 5:04 PM, David Epstein <david.epst...@warwick.ac.uk> wrote: > lm(height ~ ., data=X) > works fine. > > However > nnn <- "height" ; lm(nnn ~ . ,data=X) > fails > > How do I write such a formula, which depends on the value of a string > variable like nnn above? > > A typical application might be a program that takes a data frame containing > only numerical data, and figures out which of the columns can be best > predicted from all the other columns. > > Thanks > David > -- Sarah Goslee http://www.functionaldiversity.org ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
