On 17/04/2013 11:33 AM, Ivan Alves wrote:
Dear Duncan and A.K. Many thanks for your super quick help. The modified lapply did the trick, mapply died with a error "Error in dots[[2L]][[1L]] : object of type 'builtin' is not subsettable".
That's due to a typo: I should have said mapply(plot, g, main=names(g)) Duncan Murdoch
Kind regards, Ivan On 17 Apr 2013, at 17:12, Duncan Murdoch <murdoch.dun...@gmail.com> wrote: > On 17/04/2013 11:04 AM, Ivan Alves wrote: >> Dear all, >> >> List g has 2 elements >> >> > names(g) >> [1] "2009-10-07" "2012-02-29" >> >> and the list plot >> >> lapply(g, plot, main=names(g)) >> >> results in equal plot titles with both list names, whereas distinct titles names(g[1]) and names(g[2]) are sought. Clearly, lapply is passing 'g' in stead of consecutively passing g[1] and then g[2] to process the additional 'main' argument to plot. help(lapply) is mute as to what to element-wise pass parameters. Any suggestion would be appreciated. > > I think you want mapply rather than lapply, or you could do lapply on a vector of indices. For example, > > mapply(plot, g, main=names) > > or > > lapply(1:2, function(i) plot(g[[i]], main=names(g)[i])) > > Duncan Murdoch
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