Hi, Try: set.seed(25) g<- list(sample(1:40,20,replace=TRUE),sample(40:60,20,replace=TRUE)) names(g)<- c("2009-10-07","2012-02-29") pdf("Trialnew.pdf") lapply(seq_along(g),function(i) plot(g[[i]],main=names(g)[i])) dev.off() A.K.
----- Original Message ----- From: Ivan Alves <pap: u...@me.com> To: "R-help@r-project.org" <R-help@r-project.org> Cc: Sent: Wednesday, April 17, 2013 11:04 AM Subject: [R] use of names() within lapply() Dear all, List g has 2 elements > names(g) [1] "2009-10-07" "2012-02-29" and the list plot lapply(g, plot, main=names(g)) results in equal plot titles with both list names, whereas distinct titles names(g[1]) and names(g[2]) are sought. Clearly, lapply is passing 'g' in stead of consecutively passing g[1] and then g[2] to process the additional 'main' argument to plot. help(lapply) is mute as to what to element-wise pass parameters. Any suggestion would be appreciated. Kind regards, Ivan ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.