If you don't have to be finicky about leading zeros, the easy way is:
as.character(asd,format="%d/%m/%Y")
?strptime
If you are going to be finicky, then
asdlt <- as.POSIXlt(asd)
with(asdlt,sprintf("%d/%d/%d",mday,mon+1,year+1900))
?as.POSIXlt
?sprintf
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Sent from my phone. Please excuse my brevity.
Ron Michael <ron_michae...@yahoo.com> wrote:
>Hi,
>
>Let say I have a date variable:
>
>> asd <- as.Date("2012-01-03")
>> asd
>[1] "2012-01-03"
>
>
>
>Now, I want to express this date like 3/1/2012.
>
>can somebody help me how to achieve that?
>
>Thanks,
>
>______________________________________________
>R-help@r-project.org mailing list
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide
>http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
