try this:

> asd <- as.Date("2012-01-03")
> asd
[1] "2012-01-03"
> format(asd, format = '%m/%d/%Y')
[1] "01/03/2012"
>



On Wed, Dec 26, 2012 at 1:31 PM, Ron Michael <ron_michae...@yahoo.com> wrote:
> asd <- as.Date("2012-01-03")



-- 
Jim Holtman
Data Munger Guru

What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to