try this: > asd <- as.Date("2012-01-03") > asd [1] "2012-01-03" > format(asd, format = '%m/%d/%Y') [1] "01/03/2012" >
On Wed, Dec 26, 2012 at 1:31 PM, Ron Michael <ron_michae...@yahoo.com> wrote: > asd <- as.Date("2012-01-03") -- Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.