David,
Your results is,
> samples
[1] 111 NA 111 NA 111 NA 111 NA 111 NA
It still has NA's in it. I want it look like this,
> samples
[1] 111 111 111 111 111
thanks,
Mike
On Thu, Nov 29, 2012 at 7:55 PM, David Winsemius <dwinsem...@comcast.net>wrote:
>
> On Nov 29, 2012, at 3:25 PM, C W wrote:
>
> I want to fill up vector a with vector b.
>
>
> Vector "a"? Vector "b"?
>
> The condition is: b<200, otherwise don't fill it up.
>
>
> That would seem to be the current behavior, subject of course to an agreed
> upon definition for "filling up".
>
> It's possible , even likely, that you can get what you want with no loop
> at all.
>
> samples[ x < 200 ] <- x[ x <200 ]
>
> --
> David.
>
> Mike
>
> On Thu, Nov 29, 2012 at 6:11 PM, David Winsemius
> <dwinsem...@comcast.net>wrote:
>
>>
>> On Nov 29, 2012, at 1:55 PM, C W wrote:
>>
>> > Hi list,
>> > I am writing a for loop that looks like this:
>> > samples<-rep(NA,10)
>> > x <- rep(c(111, 225), 5)
>> > for(i in 1:10){
>> > If(x[i]<200){
>> > samples[i] <- x[i]
>> > }else{
>> > i=i-1
>>
>> If you expected the else clause to assign something to the samples
>> vector, you are mistaken.
>>
>> > }
>> > }
>> >
>> > The problem is that the returning vector still contains NA, I think
>> the i
>> > in "else" is not getting subtracted. How should I get it to work?
>>
>> You could start by telling us what you wanted to happen. You can change
>> the index of a for loop inside the body, but it will not "back up the
>> process" since at the end of the loop the next "i" will not depend on what
>> you changed it to inside the loop.
>>
>> --
>>
>> David Winsemius, MD
>> Alameda, CA, USA
>>
>>
>
> David Winsemius, MD
> Alameda, CA, USA
>
>
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