On Nov 29, 2012, at 3:25 PM, C W wrote:
> I want to fill up vector a with vector b.
Vector "a"? Vector "b"?
> The condition is: b<200, otherwise don't fill it up.
That would seem to be the current behavior, subject of course to an agreed upon
definition for "filling up".
It's possible , even likely, that you can get what you want with no loop at
all.
samples[ x < 200 ] <- x[ x <200 ]
--
David.
> Mike
>
> On Thu, Nov 29, 2012 at 6:11 PM, David Winsemius <dwinsem...@comcast.net>
> wrote:
>
> On Nov 29, 2012, at 1:55 PM, C W wrote:
>
> > Hi list,
> > I am writing a for loop that looks like this:
> > samples<-rep(NA,10)
> > x <- rep(c(111, 225), 5)
> > for(i in 1:10){
> > If(x[i]<200){
> > samples[i] <- x[i]
> > }else{
> > i=i-1
>
> If you expected the else clause to assign something to the samples vector,
> you are mistaken.
>
> > }
> > }
> >
> > The problem is that the returning vector still contains NA, I think the i
> > in "else" is not getting subtracted. How should I get it to work?
>
> You could start by telling us what you wanted to happen. You can change the
> index of a for loop inside the body, but it will not "back up the process"
> since at the end of the loop the next "i" will not depend on what you changed
> it to inside the loop.
>
> --
>
> David Winsemius, MD
> Alameda, CA, USA
>
>
David Winsemius, MD
Alameda, CA, USA
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