Hello,
Try
vec = c("1","2","3","-","-","-","4","5","6","1","2","3","-","-","-")
nms = c("A","B","C","D")
rep_vec <- rep(sapply(split(vec, cumsum(rep(c(1, 0, 0), 5))), paste,
collapse=""), 4)
mat <- matrix(rep_vec, nrow=5, byrow=TRUE, dimnames=list(NULL,nms))
mat
Hope this helps,
Rui Barradas
Em 15-06-2012 21:11, Ben quant escreveu:
Hello,
What is the fastest way to do this? I has to be done quite a few times.
Basically I have sets of 3 numbers (as characters) and sets of 3 dashes and
I have to store them in named columns. The order of the sets and the column
name they fall under is important. The actual numbers and the pattern/order
of the sets should be considered random/unpredictable.
Sample data:
vec = c("1","2","3","-","-","-","4","5","6","1","2","3","-","-","-")
rep_vec = rep(vec,times=20)
nms = c("A","B","C","D")
I need to get this:
A B C D
"123" "---" "456" "123"
"---" "123" "---" "456"
"123" "---" "123" "---"
"456" "123" "---" "123"
"---" "456" "123" "---"
Note: a matrix of 4 columns and 5 rows of concatenated string sets.
Thanks!!
Ben
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