Ben -
There are most likely faster ways, but
matrix(apply(matrix(rep_vec,ncol=3,byrow=TRUE),1,paste,collapse=''),
ncol=4,byrow=TRUE,dimnames=list(NULL,nms))
seems reasonably fast. (Do you really mean 4 columns and *5* rows?
With rep_vec = rep(vec,times=20), I get 25 rows.)
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Fri, 15 Jun 2012, Ben quant wrote:
Hello,
What is the fastest way to do this? I has to be done quite a few times.
Basically I have sets of 3 numbers (as characters) and sets of 3 dashes and
I have to store them in named columns. The order of the sets and the column
name they fall under is important. The actual numbers and the pattern/order
of the sets should be considered random/unpredictable.
Sample data:
vec = c("1","2","3","-","-","-","4","5","6","1","2","3","-","-","-")
rep_vec = rep(vec,times=20)
nms = c("A","B","C","D")
I need to get this:
A B C D
"123" "---" "456" "123"
"---" "123" "---" "456"
"123" "---" "123" "---"
"456" "123" "---" "123"
"---" "456" "123" "---"
Note: a matrix of 4 columns and 5 rows of concatenated string sets.
Thanks!!
Ben
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