Type summary.lm and read the code. Best, Uwe Ligges
Nick Chorley wrote: > Hi, > > This may be a stupid question, but how are the "std. error" values returned > by lm() calculated? For example > >> summary(lm) > > Call: > lm(formula = log10(moments[2, 1:10]) ~ log10(L_vals[1:10])) > > Residuals: > Min 1Q Median 3Q Max > -0.0052534 -0.0019473 0.0006785 0.0011740 0.0059541 > > Coefficients: > Estimate Std. Error t value Pr(>|t|) > (Intercept) -0.520639 0.002488 -209.2 3.05e-16 *** > log10(L_vals[1:10]) 0.112666 0.003446 32.7 8.35e-10 *** > > I can't find any documentation on this. > > Regards, > > Nicky Chorley > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
