Hi,
This may be a stupid question, but how are the "std. error" values returned
by lm() calculated? For example
> summary(lm)
Call:
lm(formula = log10(moments[2, 1:10]) ~ log10(L_vals[1:10]))
Residuals:
Min 1Q Median 3Q Max
-0.0052534 -0.0019473 0.0006785 0.0011740 0.0059541
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) -0.520639 0.002488 -209.2 3.05e-16 ***
log10(L_vals[1:10]) 0.112666 0.003446 32.7 8.35e-10 ***
I can't find any documentation on this.
Regards,
Nicky Chorley
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