On Nov 20, 2011, at 7:26 PM, 屠鞠传礼 wrote:

Thank you very much :)
I search on net and find sometimes response value in logistic model can have more than 2 values, and the way of this kinds of regression is called "Ordinal Logistic Regression". and even we can caculate it by the same way I mean glm in R.
here are some references:
1. http://en.wikipedia.org/wiki/Ordered_logit
2. http://www.stat.ubc.ca/~rollin/teach/643w04/lec/node62.html
above two tell us what is "Ordinal Logistic Regression".
3. http://www.ats.ucla.edu/stat/r/dae/ologit.htm
this show that we can use glm to model it

When I looked through the UCLA code it appeared they were using the Design package (now superseded by the `rms` package) and that the function was `lrm` rather than `glm`. In addition to Harrell's excellent text which has a full chapter on this topic you might also want to look at Laura Thompson's Companion to Agresti's text:

https://home.comcast.net/~lthompson221/Splusdiscrete2.pdf

--
David.


ÔÚ 2011-11-21 00:56:33£¬"Uwe Ligges" <lig...@statistik.tu- dortmund.de> дµÀ£º


On 20.11.2011 17:27, ÍÀ¾Ï´«Àñ wrote:
I worried it too, Do you have idear that what tools I can use?


Depends on your aims - what you want to do with the fitted model.
A multinomial model, some kind of discriminant analysis (lda, qda), tree based methods, svm and so son come to mind. You probably want to discuss this on some statistics mailing list/forum or among local experts rather
than on the R list. Since this is actually not that R releated.

Uwe Ligges







ÔÚ 2011-11-21 00:13:26£¬"Uwe Ligges"<lig...@statistik.tu- dortmund.de> дµÀ£º


On 20.11.2011 16:58, ÍÀ¾Ï´«Àñ wrote:
Thank you Ligges :)
one more question:
my response value "diagnostic" have 4 levels (0, 1, 2 and 3), so I use it like this:
"as.factor(diagnostic) ~ as.factor(7161521) +as.factor(2281517)"
Is it all right?


Uhh. 4 levels? Than I doubt logistic regression is the right tool for you. Please revisit the theory first: It is intended for 2 levels...


Uwe Ligges









ÔÚ 2011-11-20 23:45:23£¬"Uwe Ligges"<lig...@statistik.tu-dortmun d.de> дµÀ£º


On 20.11.2011 12:46, tujchl wrote:
HI

I use glm in R to do logistic regression. and treat both response and
predictor as factor
In my first try:

*******************************************************************************
Call:
glm(formula = as.factor(diagnostic) ~ as.factor(7161521) +
as.factor(2281517), family = binomial())

Deviance Residuals:
Min 1Q Median 3Q Max
-1.5370 -1.0431 -0.9416 1.3065 1.4331

Coefficients:
Estimate Std. Error z value Pr(>|z|)
(Intercept) -0.58363 0.27948 -2.088 0.0368 *
as.factor(7161521)2 1.39811 0.66618 2.099 0.0358 *
as.factor(7161521)3 0.28192 0.83255 0.339 0.7349
as.factor(2281517)2 -1.11284 0.63692 -1.747 0.0806 .
as.factor(2281517)3 -0.02286 0.80708 -0.028 0.9774
---
Signif. codes: 0 ¡®***¡¯ 0.001 ¡®**¡¯ 0.01 ¡®*¡¯ 0.05 ¡®.¡¯ 0.1 ¡® ¡¯ 1

(Dispersion parameter for binomial family taken to be 1)

Null deviance: 678.55 on 498 degrees of freedom
Residual deviance: 671.20 on 494 degrees of freedom
AIC: 681.2

Number of Fisher Scoring iterations: 4
*******************************************************************************

And I remodel it and *want no intercept*:
*******************************************************************************
Call:
glm(formula = as.factor(diagnostic) ~ as.factor(2281517) +
as.factor(7161521) - 1, family = binomial())

Deviance Residuals:
Min 1Q Median 3Q Max
-1.5370 -1.0431 -0.9416 1.3065 1.4331

Coefficients:
Estimate Std. Error z value Pr(>|z|)
as.factor(2281517)1 -0.5836 0.2795 -2.088 0.0368 *
as.factor(2281517)2 -1.6965 0.6751 -2.513 0.0120 *
as.factor(2281517)3 -0.6065 0.8325 -0.728 0.4663
as.factor(7161521)2 1.3981 0.6662 2.099 0.0358 *
as.factor(7161521)3 0.2819 0.8325 0.339 0.7349
---
Signif. codes: 0 ¡®***¡¯ 0.001 ¡®**¡¯ 0.01 ¡®*¡¯ 0.05 ¡®.¡¯ 0.1 ¡® ¡¯ 1

(Dispersion parameter for binomial family taken to be 1)

Null deviance: 691.76 on 499 degrees of freedom
Residual deviance: 671.20 on 494 degrees of freedom
AIC: 681.2

Number of Fisher Scoring iterations: 4
*******************************************************************************

*As show above in my second model it return no intercept but look this:
Model1:
(Intercept) -0.58363 0.27948 -2.088 0.0368 *
Model2:
as.factor(2281517)1 -0.5836 0.2795 -2.088 0.0368 **

They are exactly the same. Could you please tell me what happen?

Actually it does not make sense to estimate the model without an
intercept unless you assume that it is exactly zero for the first levels of your factors. Think about the contrasts you are interested in. Looks
like not the default?

Uwe Ligges



Thank you in advance


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