On Aug 25, 2011, at 1:30 PM, Claudio Zanettini wrote:

I tried setting ylim=(0, 1000)
but the segment that I have draw is at y=-10
so if I set the y origin to 0 I don t have the segment,
if a l leave it at -10 I have the segment but the axis start from -10.

I would like to have both.
So to have a graph with ylim=( 0, 1000)
and under it a segment parallel to the x axis at  -10.

If you really want that then you will need to look at the xpd parameter for par.

I am sorry it is contorted thing :)

Claudio

If instead you want to plot at y= -10 without changing xpd, then set axes=FALSE in the plot command and then construct your x and y axes separately to your specifications. Any more specific comments will require that you present code (as well as a better description) that constructs an example.

--
David.


2011/8/25 R. Michael Weylandt <michael.weyla...@gmail.com>

"lim" is not the argument: "ylim" is.

You put in a vector of length 2 comprising the min and max y you wish:
consider this:

x = -5:5; y = x^2; z = rep(-5,11);
layout(1:2)
plot(x,y,type="b"); lines(x,z,col=2)
plot(x,y,ylim = c(-8,max(y)+3),type="b"); lines(x,z,col=2)

For your work, you'd need ylim = c(0, 1.03*max(y)) or something similar.

Michael Weylandt


On Thu, Aug 25, 2011 at 1:12 PM, Claudio Zanettini <
claudio.zanett...@gmail.com> wrote:

Yes I tried but if I set the lim to 0 then it will not displayed the line
that is at -10, right?

2011/8/25 R. Michael Weylandt <michael.weyla...@gmail.com>

Look at ylim, as an optional argument to plot.

Michael

On Thu, Aug 25, 2011 at 1:07 PM, Claudio Zanettini <
claudio.zanett...@gmail.com> wrote:

Hello everyone,
I have a graph and a segment parallel to the x axis at y=-10, x=0,
and
bars on it.
Now the question is,
Is there a way to leave the segment there but let the graph axis start
from
the origin?
In this way the segment will be out of the graph


Thanks

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West Hartford, CT

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