> I tried setting ylim=(0, 1000)
> but the segment that I have draw is at y=-10
> so if I set the y origin to 0 I don t have the segment,
> if a l leave it at -10 I have the segment but the axis start from -10.
>
> I would like to have both.
> So to have a graph with ylim=( 0, 1000)
> and under it a segment parallel to the x axis at -10.
> I am sorry it is contorted thing :)
>
> Claudio
>
>
> 2011/8/25 R. Michael Weylandt <michael.weyla...@gmail.com>
>
>> "lim" is not the argument: "ylim" is.
>>
>> You put in a vector of length 2 comprising the min and max y you wish:
>> consider this:
>>
>> x = -5:5; y = x^2; z = rep(-5,11);
>> layout(1:2)
>> plot(x,y,type="b"); lines(x,z,col=2)
>> plot(x,y,ylim = c(-8,max(y)+3),type="b"); lines(x,z,col=2)
>>
>> For your work, you'd need ylim = c(0, 1.03*max(y)) or something similar.
>>
>> Michael Weylandt
>>
>>
>> On Thu, Aug 25, 2011 at 1:12 PM, Claudio Zanettini <
>> claudio.zanett...@gmail.com> wrote:
>>
>>> Yes I tried but if I set the lim to 0 then it will not displayed the line
>>> that is at -10, right?
>>>
>>> 2011/8/25 R. Michael Weylandt <michael.weyla...@gmail.com>
>>>
>>> Look at ylim, as an optional argument to plot.
>>>>
>>>> Michael
>>>>
>>>> On Thu, Aug 25, 2011 at 1:07 PM, Claudio Zanettini <
>>>> claudio.zanett...@gmail.com> wrote:
>>>>
>>>>> Hello everyone,
>>>>> I have a graph and a segment parallel to the x axis at y=-10, x=0,
>>>>> and
>>>>> bars on it.
>>>>> Now the question is,
>>>>> Is there a way to leave the segment there but let the graph axis start
>>>>> from
>>>>> the origin?
>>>>> In this way the segment will be out of the graph
>>>>>
>>>>>
>>>>> Thanks
>>>>>
>>>>> [[alternative HTML version deleted]]
>>>>>
>>>>> ______________________________________________
>>>>> R-help@r-project.org mailing list
>>>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>>>> PLEASE do read the posting guide
>>>>> http://www.R-project.org/posting-guide.html
>>>>> and provide commented, minimal, self-contained, reproducible code.
>>>>>
>>>>
>>>>
>>>
>>
>
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