On Aug 24, 2011, at 1:11 PM, Sebastian Bauer wrote:
Hi!
I'd like to rank rows of a data frame similar to what rank() does
for vectors. However, ties should be broken by columns that I
specify. If it is not possible to break a ties (because the row data
is essentially the same), I'd like to have the same flexibility that
rank() offers. Is there an elegant solution to this simple problem
in R? Basically, what I need is a mixture of order() and rank().
While the former allows to specify multiple vectors, it doesn't
provide the flexibility of rank() such that I can specify what
happens if ties can not be broken.
An example of this "simple problem" would clarify this greatly. I
cannot tell what "flexibility" in 'rank' is missing in 'order'.
Thanks for your answer. For instance, if I have two vectors such as
1 1
1 2
1 2
1 3
2 1
that I want combinedly ranked. I'd like to get an output
1
2
2
4
5
or (ties.method=average)
1
2.5
2.5
4
5
Basically, I need a function similar to the rank() function that
accepts
more than one vector (as order() does).
Can't you just paste the columns and run rank on the results? 'rank'
accepts character vectors.
Best,
Sebastian
David Winsemius, MD
West Hartford, CT
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