Hi! >> I'd like to rank rows of a data frame similar to what rank() does >> for vectors. However, ties should be broken by columns that I >> specify. If it is not possible to break a ties (because the row data >> is essentially the same), I'd like to have the same flexibility that >> rank() offers. Is there an elegant solution to this simple problem >> in R? Basically, what I need is a mixture of order() and rank(). >> While the former allows to specify multiple vectors, it doesn't >> provide the flexibility of rank() such that I can specify what >> happens if ties can not be broken. > An example of this "simple problem" would clarify this greatly. I > cannot tell what "flexibility" in 'rank' is missing in 'order'.
Thanks for your answer. For instance, if I have two vectors such as 1 1 1 2 1 2 1 3 2 1 that I want combinedly ranked. I'd like to get an output 1 2 2 4 5 or (ties.method=average) 1 2.5 2.5 4 5 Basically, I need a function similar to the rank() function that accepts more than one vector (as order() does). Best, Sebastian ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
