Hi,
I have two lists (c and h - see below) containing matrices with similar
cases but different values. I want to split these matrices into multiple
matrices based on the values in h. So, I did the following:
years<-c(1997:1999)
for (t in 1:length(years))
{
year=as.character(years[t])
h[[year]]<-sapply(colnames(h[[year]]), function(var)
h[[year]][h[[year]][,var]>0, h[[year]][var,]>0])
}
Now that I have created list h (with split matrices), I would like to use
these selections to make similar selections in list c. List c needs to get
the exact same shape as h, so that `8026`in 1997 (c$`1997`$`8026`) looks
like this:
$`1997`$`8026`
B
B 8025 8026 8029
8025 1.0000000 0.7739527 0.9656091
8026 0.7739527 1.0000000 0.7202771
8029 0.9656091 0.7202771 1.0000000
Can anyone help me doing this? I have no idea how I can get it to work.
Thank you very much for your help!
library(zoo)
DF1 = data.frame(read.table(textConnection(" B C D E F G
8025 1995 0 4 1 2
8025 1997 1 1 3 4
8026 1995 0 7 0 0
8026 1996 1 2 3 0
8026 1997 1 2 3 1
8026 1998 6 0 0 4
8026 1999 3 7 0 3
8027 1997 1 2 3 9
8027 1998 1 2 3 1
8027 1999 6 0 0 2
8028 1999 3 7 0 0
8029 1995 0 2 3 3
8029 1998 1 2 3 2
8029 1999 6 0 0 1"),head=TRUE,stringsAsFactors=FALSE))
a <- read.zoo(DF1, split = 1, index = 2, FUN = identity)
sum.na <- function(x) if (any(!is.na(x))) sum(x, na.rm = TRUE) else NA
b <- rollapply(a, 3, sum.na, align = "right", partial = TRUE)
newDF <- lapply(1:nrow(b), function(i)
prop.table(na.omit(matrix(b[i,], nc = 4, byrow = TRUE,
dimnames = list(unique(DF1$B), names(DF1)[-1:-2]))), 1))
names(newDF) <- time(a)
c<-lapply(newDF, function(mat) tcrossprod(mat / sqrt(rowSums(mat^2))))
DF2 = data.frame(read.table(textConnection(" A B C
80 8025 1995
80 8026 1995
80 8029 1995
81 8026 1996
82 8025 1997
82 8026 1997
83 8025 1997
83 8027 1997
90 8026 1998
90 8027 1998
90 8029 1998
84 8026 1999
84 8027 1999
85 8028 1999
85 8029 1999"),head=TRUE,stringsAsFactors=FALSE))
e <- function(y) crossprod(table(DF2[DF2$C %in% y, 1:2]))
years <- sort(unique(DF2$C))
f <- as.data.frame(embed(years, 3))
g<-lapply(split(f, f[, 1]), e)
h<-lapply(g, function (x) ifelse(x>0,1,0))
--
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