Re: [R] For help in R coding

[David Winsemius]

On Jul 2, 2011, at 12:34 PM, Bansal, Vikas wrote:
Dear all,

I am doing a project on variant calling using R.I am working on
pileup file.There are 10 columns in my data frame and I want to
count the number of A,C,G and T in each row for column 9.example of
column 9 is given below-

         .a,g,,
         .t,t,,
         .,c,c,
         .,a,,,
         .,t,t,t
         .c,,g,^!.
         .g,ggg.^!,
         .$,,,,,.,
         a,g,,t,
         ,,,,,.,^!.
         ,$,,,,.,.

This is a bit confusing for me as these characters are in one column
and how can we scan them for each row to print number of A,C,G and T
for each row.
Seems a bit clunky but this does the job (first the data):
txt <- " .a,g,,
+            .t,t,,
+            .,c,c,
+            .,a,,,
+            .,t,t,t
+            .c,,g,^!.
+            .g,ggg.^!,
+            .$,,,,,.,
+            a,g,,t,
+            ,,,,,.,^!.
+            ,$,,,,.,."

txtvec <- readLines(textConnection(txt))
Now the clunky solution, Basically subtracts 1 from the counts of
"fragments" that result from splitting on each letter in turn. Could
be made prettier with a function that did the job.

data.frame(A = unlist(lapply( lapply( sapply(txtvec, strsplit,
split="a"), length) , "-", 1)),
+ C = unlist(lapply( lapply( sapply(txtvec, strsplit, split="c"),
length) , "-", 1)),
+ G = unlist(lapply( lapply( sapply(txtvec, strsplit, split="g"),
length) , "-", 1)),
+ T = unlist(lapply( lapply( sapply(txtvec, strsplit, split="t"),
length) , "-", 1)) )
                     A C G T
.a,g,,               1 0 1 0
          .t,t,,     0 0 0 2
          .,c,c,     0 2 0 0
          .,a,,,     1 0 0 0
          .,t,t,t    0 0 0 2
          .c,,g,^!.  0 1 1 0
          .g,ggg.^!, 0 0 4 0
          .$,,,,,.,  0 0 0 0
          a,g,,t,    1 0 1 1
          ,,,,,.,^!. 0 0 0 0
          ,$,,,,.,.  0 0 0 0

Has the advantage that the input data ends up as rownames, which  
was a
surprise.

If you wanted to count "A" and "a" as equivalent, then the split
argument should be "a|A"


AS YOU MENTIONED THAT IF I WANT TO COUNT A AND a I SHOULD SPLIT  
LIKE THIS.
BUT CAN I COUNT . AND , ALSO USING-
data.frame(A = unlist(lapply( lapply( sapply(txtvec, strsplit,
split=".|,"), length) , "-", 1)),

I TRIED IT BUT ITS NOT WORKING.IT IS GIVING THE OUTPUT BUT AT SOME  
PLACES IT IS SHOWING MORE NUMBER OF . AND , AND SOMEWHERE IT IS NOT  
EVEN CALCULATING AND JUST SHOWING 0.
You need to use valid regex expressions for 'split'. Since "." and ","  
are special characters they need to be escaped when you wnat the  
literals to be recognized as such.
I haven't figured out why but you need to drop the final operation of  
subtracting 1 from the values when counting commas:
data.frame(periods = unlist(lapply( lapply( sapply(txtvec, strsplit,
                             split="\\."), length) , "-", 1))
 ,commas = unlist( lapply( sapply(txtvec, strsplit,
                             split="\\,"), length) ) )
                       periods commas
 .a,g,,                      1      3
            .t,t,,           1      3
            .,c,c,           1      3
            .,a,,,           1      4
            .,t,t,t          1      4
            .c,,g,^!.        1      4
            .g,ggg.^!,       2      2
            .$,,,,,.,        2      6
            a,g,,t,          0      4
            ,,,,,.,^!.       1      7
            ,$,,,,.,.        1      7

--

David Winsemius, MD
West Hartford, CT

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