On Feb 19, 2011, at 8:40 AM, Umesh Rosyara wrote:
Just a correction. My expected outdata frame was somehow distorted
to a
single, one column. So correct one is:
marker1a markerb marker2a marker2b
1 1 1 1
1 3 1 3
3 3 3 3
3 3 3 3
1 3 1 3
1 3 1 3
func <- function(x) {sapply( strsplit(x, ""),
match, table= c("A", NA, "C"))}
t( apply(dfr, 1, func) )
[,1] [,2] [,3] [,4]
[1,] 1 1 1 1
[2,] 1 3 1 3
[3,] 3 3 3 3
[4,] 3 3 3 3
[5,] 1 3 1 3
[6,] 1 3 1 3
It's amatrix rather than a dataframe and doesn't have colnames but
that should be trivial to fix.
Thanks;
Umesh R
_____
From: Umesh Rosyara [mailto:rosyar...@gmail.com]
Sent: Friday, February 18, 2011 10:09 PM
To: 'Joshua Wiley'
Cc: 'r-help@r-project.org'
Subject: RE: [R] recoding a data in different way: please help
Hi Josh and R community members
Thank you for quick response. I am impressed with the help.
To solve my problems, I tried recode options and I had the following
problem
and which motivated me to leave it. Thank you for remind me the option
again, might help to solve my problem in different way.
marker1 <- c("AA", "AC", "CC", "CC", "AC", "AC")
marker2 <- c("AA", "AC", "CC", "CC", "AC", "AC")
dfr <- data.frame(cbind(marker1, marker2))
Objective: replace A with 1, C with 3, and split AA into 1 1 (two
columns
numeric). So the intended output for the above dataframe is:
marker1a
markerb
marker2a
marker2b
1
1
1
1
1
3
1
3
3
3
3
3
3
3
3
3
1
3
1
3
1
3
1
3
I tried the following:
for(i in 1:length(dfr))
{
dfr[[i]]=recode (dfr[[i]],"c('AA')= '1,1'; c('AC')= '1,3';
c('CA')=
'1,3'; c('CC')= '3,3' ")
}
write.table(dfr,"dfr.out", sep=" ,", col.names = T)
dfn=read.table("dfr.out",header=T, sep="," )
# just trying to cheat R, unfortunately the marker1 and marker columns
remained non-numeric, even when opened in excel !!
Unfortunately I got the following result !
marker1 marker2
1 1,1 1,1
2 1,2 1,2
3 2,2 2,2
4 2,2 2,2
5 1,2 1,2
6 1,2 1,2
Sorry to bother all of you, but simple things are being complicated
these
days to me.
Thank you so much
Umesh R
_____
From: Joshua Wiley [mailto:jwiley.ps...@gmail.com]
Sent: Friday, February 18, 2011 12:15 AM
Cc: r-help@r-project.org
Subject: Re: [R] recoding a data in different way: please help
Dear Umesh,
I could not figure out exactly what your recoding scheme was, so I do
not have a specific solution for you. That said, the following
functions may help you get started.
?ifelse # vectorized and different from using if () statements
?if #
?Logic ## logical operators for your tests
## if you install and load the "car" package by John Fox
?recode # a function for recoding in package "car"
I am sure it is possible to string together some massive series of if
statements and then use a for loop, but that is probably the messiest
and slowest possible way. I suspect there will be faster, neater
options, but I cannot say for certain without having a better feel for
how all the conditions work.
Best regards,
Josh
On Thu, Feb 17, 2011 at 6:21 PM, Umesh Rosyara <rosyar...@gmail.com>
wrote:
Dear R users
The following question looks simple but I have spend alot of time
to solve
it. I would highly appeciate your help.
I have following dataset from family dataset :
Here we have individuals and their two parents and their marker
scores
(marker1, marker2,....and so on). 0 means that their parent
information
not
available.
Individual Parent1 Parent2 mark1 mark2
1 0 0 12 11
2 0 0 11 22
3 0 0 13 22
4 0 0 13 11
5 1 2 11 12
6 1 2 12 12
7 3 4 11 12
8 3 4 13 12
9 1 4 11 12
10 1 4 11 12
I want to recode mark1 and other mark2.....and so on column by
looking
indvidual parent (Parent1 and Parent2).
For example
Take case of Individual 5, who's Parent 1 is 1 (has mark1 score 12)
and
Parent 2 is 2 (has mark1 score 11). Individual 5 has mark1 score 11.
Suppose
I have following condition to recode Individual 5's mark1 score:
For mark1 variable, If Parent1 score "11" and Parent2 score "22" and
recode
indvidual 5's score, "12"=1, else 0
If Parent1 score "12" and Parent2
score
"22" and recode individual 5's score, "22"=1, "12"= 0.5, else 0
.........................more
conditions
Similarly the pointer should move from individual 5 to n
individuals at
the
end of the file.
Thank you in advance
Umesh R
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--
Joshua Wiley
Ph.D. Student, Health Psychology
University of California, Los Angeles
http://www.joshuawiley.com/
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______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
West Hartford, CT
______________________________________________
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
