Hi:
This is as far as I could get:
df <- read.table(textConnection("
Individual Parent1 Parent2 mark1 mark2
1 0 0 12 11
2 0 0 11 22
3 0 0 13 22
4 0 0 13 11
5 1 2 11 12
6 1 2 12 12
7 3 4 11 12
8 3 4 13 12
9 1 4 11 12
10 1 4 11 12"), header = TRUE)
df2 <- transform(df, Parent1 = replace(Parent1, Parent1 == 0, NA),
Parent2 = replace(Parent2, Parent2 == 0, NA))
df2 <- transform(df2, imark1p1 = df2$mark1[df2$Parent1], # Parent 1's
mark1
imark1p2 = df2$mark1[df2$Parent2],
# Parent 2's mark1
imark2p1 = df2$mark2[df2$Parent1],
# Parent 1's mark2
imark2p2 = df2$mark2[df2$Parent2])
# Parent 2's mark2
I created df2 so as not to overwrite the original in case of a mistake. At
this point, you have several sets of vectors that you can compare; e.g.,
mark1 with imark1p1 and imark1p2. Like Josh, I couldn't make heads or tails
out of what these logical tests were meant to output, but perhaps this gives
you a broader template with which to work. At this point, you can probably
remove the rows corresponding to the parents. I believe ifelse() is your
friend here - it can perform logical tests in a vectorized fashion. As long
as the tests are consistent from one individual to the next, it's likely to
be an efficient route.
HTH,
Dennis
On Thu, Feb 17, 2011 at 6:21 PM, Umesh Rosyara <rosyar...@gmail.com> wrote:
> Dear R users
>
> The following question looks simple but I have spend alot of time to solve
> it. I would highly appeciate your help.
>
> I have following dataset from family dataset :
>
> Here we have individuals and their two parents and their marker scores
> (marker1, marker2,....and so on). 0 means that their parent information not
> available.
>
>
> Individual Parent1 Parent2 mark1 mark2
> 1 0 0 12 11
> 2 0 0 11 22
> 3 0 0 13 22
> 4 0 0 13 11
> 5 1 2 11 12
> 6 1 2 12 12
> 7 3 4 11 12
> 8 3 4 13 12
> 9 1 4 11 12
> 10 1 4 11 12
>
> I want to recode mark1 and other mark2.....and so on column by looking
> indvidual parent (Parent1 and Parent2).
>
> For example
>
> Take case of Individual 5, who's Parent 1 is 1 (has mark1 score 12) and
> Parent 2 is 2 (has mark1 score 11). Individual 5 has mark1 score 11.
> Suppose
> I have following condition to recode Individual 5's mark1 score:
>
> For mark1 variable, If Parent1 score "11" and Parent2 score "22" and recode
> indvidual 5's score, "12"=1, else 0
> If Parent1 score "12" and Parent2 score
> "22" and recode individual 5's score, "22"=1, "12"= 0.5, else 0
> .........................more conditions
>
> Similarly the pointer should move from individual 5 to n individuals at the
> end of the file.
>
> Thank you in advance
>
> Umesh R
>
>
>
>
>
> [[alternative HTML version deleted]]
>
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>
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