Hi Rex, Thanks, this is exactly what I want but have to do it with many big arrays ... thus if there were a way to do it with a vectorized function would it not be a lot more efficient?
Much appreciated! J >Subject: RE: sort a 3 dimensional array across third dimension ? > >Although I suggested to someone else that for-loops be avoided, they are >not in the inner loop in this code, and it's probably easier to >understand than some sort of apply: > >a = array(round(100*runif(60)),dim=c(3,4,5)) >a >for (i in 1:dim(a)[1]) > for (j in 1:dim(a)[2]) > a[i,j,] = sort(a[i,j,]) >a > >Is that what you want? > >Subject: [R] sort a 3 dimensional array across third dimension ? > >I'm attempting to sort a 3 dimensional array that looks like this >> x >, , 1 > [,1] [,2] >[1,] 9 9 >[2,] 7 9 >, , 2 > [,1] [,2] >[1,] 6 5 >[2,] 4 6 >, , 3 > [,1] [,2] >[1,] 2 1 >[2,] 3 2 > >Such that it ends up like this .... >> y >, , 1 > [,1] [,2] >[1,] 2 1 >[2,] 3 2 >, , 2 > [,1] [,2] >[1,] 6 5 >[2,] 4 6 >, , 3 > [,1] [,2] >[1,] 9 9 >[2,] 7 9 > >I think this is sorting across the third dimension but several attempts >using either the sort or apply functions have not worked. Any and all >suggestions most welcome. Thanks > >J > >=============================== >Dr. Jim Maas >University of East Anglia > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
