Although I suggested to someone else that for-loops be avoided, they are not in the inner loop in this code, and it's probably easier to understand than some sort of apply:
a = array(round(100*runif(60)),dim=c(3,4,5)) a for (i in 1:dim(a)[1]) for (j in 1:dim(a)[2]) a[i,j,] = sort(a[i,j,]) a Is that what you want? -----Original Message----- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Maas James Dr (MED) Sent: Friday, February 18, 2011 8:01 AM To: r-help@r-project.org Subject: [R] sort a 3 dimensional array across third dimension ? I'm attempting to sort a 3 dimensional array that looks like this > x , , 1 [,1] [,2] [1,] 9 9 [2,] 7 9 , , 2 [,1] [,2] [1,] 6 5 [2,] 4 6 , , 3 [,1] [,2] [1,] 2 1 [2,] 3 2 Such that it ends up like this .... > y , , 1 [,1] [,2] [1,] 2 1 [2,] 3 2 , , 2 [,1] [,2] [1,] 6 5 [2,] 4 6 , , 3 [,1] [,2] [1,] 9 9 [2,] 7 9 I think this is sorting across the third dimension but several attempts using either the sort or apply functions have not worked. Any and all suggestions most welcome. Thanks J =============================== Dr. Jim Maas University of East Anglia [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. message may contain confidential information. If you are not the designated recipient, please notify the sender immediately, and delete the original and any copies. Any use of the message by you is prohibited. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
