Try this: noquote("lm(y ~ X2 + X3 + X4)")
To remove X characters: gsub("^.|.$", "", "lm(y ~ X2 + X3 + X4)") On Tue, Dec 14, 2010 at 6:27 PM, Mark Na <mtb...@gmail.com> wrote: > Hi R-helpers, > > I have a character string, for example: > > "lm(y ~ X2 + X3 + X4)" > > from which I would like to strip off the leading and trailing > quotation marks resulting in this: > > lm(y ~ X2 + X3 + X4) > > > I have tried using gsub() but I can't figure out how to specify the > quotation mark using a regular expression. > > Alternatively, I would like a function that lets me delete the leading > (or trailing) X characters, and in this case X=1 (but it could be used > more flexibly to delete several leading or trailing characters). > > I would appreciate help with either of these potential solutions (gsub > and regex, or delete leading/trailing characters). > > Many thanks! > > Mark > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O [[alternative HTML version deleted]]
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.