Hi R-helpers, I have a character string, for example:
"lm(y ~ X2 + X3 + X4)" from which I would like to strip off the leading and trailing quotation marks resulting in this: lm(y ~ X2 + X3 + X4) I have tried using gsub() but I can't figure out how to specify the quotation mark using a regular expression. Alternatively, I would like a function that lets me delete the leading (or trailing) X characters, and in this case X=1 (but it could be used more flexibly to delete several leading or trailing characters). I would appreciate help with either of these potential solutions (gsub and regex, or delete leading/trailing characters). Many thanks! Mark ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
