Thank you. I tried this but not sure if I have implemented this correctly ... basically if function1 hangs .. I need the timeout to be triggered and then the process moves to the next function call.
I have this: function1 <- function(x){ setTimeLimit(elapsed = 5*60, transient = FALSE) step 1 step 2 step 3 } #Code to execute about function repeatedly. It moves to a new input variable when I call it back through a parameter repeat{ function1(x) } -----Original Message----- From: Prof Brian Ripley [mailto:rip...@stats.ox.ac.uk] Sent: 07 December 2010 13:23 To: Santosh Srinivas Cc: r-help@r-project.org Subject: Re: [R] Time out for a R Function On Tue, 7 Dec 2010, Santosh Srinivas wrote: > Hello Group, > > I have an R-function that works fine for most part but sometime runs into a > long loop! (I'm lazy and short on time to debug right now so want to do > something easy) > For my purpose, it is ok to make few errors .... is there a way I can put a > timeout on a function and the r-process needes to move on to the next step? See the help on setTimeLimit(transient = FALSE) . Unlike other suggestions, that does not need you to change the code to check the time. -- Brian D. Ripley, rip...@stats.ox.ac.uk Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UK Fax: +44 1865 272595 ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.